The Buchla Music Easel, which consists of a Buchla 208 Programmable Sound Source and a Buchla 218 Model Keyboard together in a single case, is one of the rarest and most coveted of the Buchla designs. To put yourself in the right frame of mind for this homework, you should listen to mp3's by Charles Cohen, who performs live exclusively using a Music Easel. (He collaborates with other musicians, so not everything you're hearing is the Easel.)
Ground rules on this homework: You may verbally discuss approaches to the problems with each other while looking at the schematics, and are encouraged to do so; but you may not look at each other's written solutions or ask "what did you get on part XYZ of problem ABC." (In future homeworks, I will allow varying degrees of explicit collaboration on certain problems.)
IC 20 is a TL082, which has the high input impedance (and hence low unwanted input currents) that you'd want in an op amp playing the role of an integrator. Note that Buchla uses a voltage divider to put 7.5 V on the positive input terminal of IC 20; I'm not sure why. I think it may have something to do with biasing the transistors that for the current-switching OTA (Q6, Q7, and Q8) correctly, but I'm not sure. (To be honest, I'm not hip enough with transistors to really know what's going on; I just know that when I see BJTs in that configuration, it's an OTA. Any ECE3050 gurus in the class who can enlighten us?) Anyway, you don't need to worry about it; remember, that there's nothing that guarantees that any integrator starts out with an output at zero volts when you fire up a synth anyway.
IC 21 implements a special feature that allows you to lock this oscillator to another oscillator; this feature will be unused in our analysis, so assume that the output of IC 21 is zero volts.
Fasten your seat belts - this may get bumpy:
a) Let's look IC 22, which is an LM311 comparitor. C20A (220 pF) and R164A (10K) seem like the usual goo you find hanging off of an LM311. Let's ignore C20A and R164A, treat the comparitor as ideal (i.e. effectively infinite input impedance), and image that the output of the comparator is tied to its + terminal. The LM311 has an "open collector" output. If the voltage at the - terminal is greater than the voltage at the + terminal, the output is forced to the negative supply rail of the LM311, which here is 0 V. If the voltage at the - less than the voltage at the + terminal, then the LM311 "lets go" of the output, and the output goes to the voltage set by the resistive voltage divider consisting of R155 (4.99K to ground), R156 (10K to 15 V), and R164 (24K to 0 V).
Show that these assumptions give 4.39 V, unlike the 4.29 V shown on the schematic. Let's use that 4.39 V number, since it gives a better-centered triangle in the end. :)
b) The triangle wave output is taken from the output of IC 20, which forms the integrator along with C20. Note that the output of the integrator is fed to the the - terminal of IC 22 via a resistive divider (R153, 4.99K from the output of the integrator to the - terminal of the comparator, and R154, 28.7K from the - terminal of the the comparator to the +15 V supply). (When I first did my analysis, I couldn't read the 28.7K; I thought it was 20.7K or 26.7K and came up with strange answers. After some confusion, I contacted People In The Know and found out that it's 28.7K.)
Let's call the output of IC20 "vtri" (where "tri" is a subscript). What values of vtri correspond to values of 0 V and 4.39 V at the - input to the comparitor? This tells you what voltages the triangle wave swings between.
c) What is the DC value of the triangle wave? What percentage is this relative to the full peak-to-peak swing of the triangle wave?
d) Pretending for a moment that Q7 had infinite input impedance at its base, find is the voltage at the base of Q7 defined by the resistive divider consisting of R131 (let's suppose the hard to read smudge is 22K) and R132 (100K). Note that the difference between 0 V and this value, and 4.39 V and this value, are both well outside of the +/- 10 mV "linear" range of most OTA. Let's call the current flowing into the collector of the right transistor of the Q5 NPN matched pair (that's an AD811, which is nearly impossible to find now; if you were trying to build your own Buchla 259, you'd want to use something like a MAT02, SSM2210, LM394, or LS318 instead) "Icon" (where the "con" is a subscript); let's also suppose that the OTA is being driven so hard that it essentially acting as a switch (we're so far into the "tanh" function that it's approximately one), so a current of Icon is either flowing into out out of C20, depending on which way the triangle is going. Note that Q7 will typically sink some current through it's base, so the voltage won't be what we computed, but our overall conclusion, that the OTA is operation in saturation, still applies.
e) No units are specified for C20, but after looking at many other VCO designs, I strongly suspect that C20 is 4.7 nF; let's use that value. Find the Icon that would result in a triangle wave with a pitch of 261.63 Hz, which is "middle C." Remember that for a full period of the triangle wave, the wave has to travel both up and down.
Our analysis above made a lot of assumptions; in particular, there's probably some current sunk through Q8, and probably a bit of current sunk through the + terminal of the comparitor (IC22), so the top voltage of the square wave is probably more like 4.29 V than 4.39, making the DC offset worse; but considering the tolerences on all the various components, this isn't that big of a deal.
You always need a few trimpots here and there to get VCOs in tune.
a) Is the MOSFET an n-channel or a p-channel MOSFET?
b) Assuming perfect "zero tolerance" resistors, compute the threshold set at the negative terminal of the LM311 to three places after the decimal point. Of course, with practical resistors, this is "close enough to 1 V. (Don't worry about the capacitor; it's just there to bypass assorted unwanted goo.)
c) Let's call the current flowing into the collector of the right transistor of the 2SC1583 NPN pair (that's what's used in the Roland TB-303; they're out of production, but Limor is selling leftovers from her xoxbox project; I'll get some for you to play with) "Icon," where "con" is a subscript. Find the value of Icon that would give a pitch of 4186 Hz, which is corresponds to the highest note available (a "C") on a standard piano.
d) When the sawtooth wave < 1 V, what voltage is applied to the MOSFET gate?
e) When the sawtooth wave exceeds 1 V, what voltage is applied to the MOSFET gate? Remember in this case, the LM311 "lets go" of its "open collector" output. Assume the diode in the upper right hand corner has a drop of 0.7 V, and ignore the 100 pF cap. Note that Ian is using a 5.6 V zener to set a voltage of 6.4 V at pin 8 of the LM311.